Do you know that there is an easy way to find the remainder when a number is divided by 9?
Example 1:
43 ÷ 9 = 4, remainder = 7
quick remainder: 4 + 3 = 7
Example 2:
28 ÷ 9 = 3, remainder = 1
quick remainder: 2 + 8 = 10 ?
If the addition is ? 9, cast out the 9s, until it is lest than 9.
10 – 9 = 1
Example 3:
2345 ÷ 9 = 260, remainder = 5
quick remainder: 2 + 3 + 4 + 5 = 14
14 – 9 = 5
Example 4:
4489 ÷ 9 = 498, remainder = 7
quick remainder: 4 + 4 + 8 + 9 = 25
25 – 9 = 16
16 – 9 = 7
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erm… tough.. haha
Crazyfool: You just need to master addition.
(Any number of 9s)*(a number less than ‘Any number of 9s’)can be multipled mentally by a Vedic-manner
is ‘a trillion times 9′
58235294117647 is a number less than’a trillion times 9′
To multiply these factors do the following
99999…………999999999999999999999 ‘a trillion times 9′
00000…………000000588235294117647 is other number
Initial steps!
00000…………000000588235294117646(one less than factor)
99999…………999999411764705882353(Vertical sum is 9)
00000…000000588235294117646,99999…999999411764705882353 is exact answer digits
Vedic sutra is “all from 9″ (Nikhilam Navatha:)
Orkut forum “Number Zero” reveals Vedic matrix and unknown ancient Indian Vedic computing manners disclosed by Shri Jagadguru Sankaracharya (1884-1960)!